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I have the following code to check if the value is Int or null and further check if it is below a certain number:

            binding.RootLayout.forEach {
                if (it is EditText) {
                    val intOrNull = it.text.toString().toIntOrNull()
                    if (intOrNull == null) {
                        count += 1
                    } else if (intOrNull > 100000) {
                        overTheLimitExist = true
The problem is, when I enter some number like 123456789 or below, it correctly identify it as (1) Int and (2) above the preset limit. However, if I enter a larger number such as 12345678900 it incorrectly identify it as null.
I search online for the toIntOrNull but they didn't say anything about a limit to the function.
                Max limit of Int is approximately 2*10^9 (4byte). Over that until approx 4*10^18 use Long(8byte). Or else BigInteger which can store number upto infinity :P (just kidding it can store upto ~18GB of RAM).
– Animesh Sahu
                Jan 10, 2021 at 8:14
12345678900 is larger than Integer's max value (2^31-1) , hence the implementation of toIntOrNull returns null, as 12345678900 doesn't fit in 4 bytes.
You can use toLongOrNull or toBigIntegerOrNull for really big numbers.
I think this problem is for limit of int type
(-2,147,483,648 to 2,147,483,647) you should use another type such as "Long" or BigNumber java class. 
you can test 1 bigger than this range (2147483648) or 1 smaller (2147483646) and see the result.
I hope this help to you. 
sorry for my English.
        
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