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i am trying to convert below XML snippet into Java version, appreciate any help here

<int:router input-channel="channel_in" default-output-channel="channel_default" 
  expression="payload.name" ignore-channel-name-resolution-failures="true">
    <int:mapping value="foo" channel="channel_one" />
    <int:mapping value="bar" channel="channel_two" />
</int:router>
Here is what i did for my concrete example 
@Router(inputChannel = "routerChannel")
    public String route(Account message) {
        if (message.getType().equals("check")) {
            return "checkChannel";
        } else if (message.getType().equals("credit")) {
            return "creditChannel";
        return "errorChannel";
@Bean
public DirectChannel checkChannel() {
    return new DirectChannel();
when i do above i am seeing below error 
org.springframework.messaging.MessageDeliveryException: Dispatcher has no subscribers for channel 'application:8090.checkChannel'.;
All the Spring Integration custom tag has a description like this:
<xsd:element name="router" type="routerType">
    <xsd:annotation>
        <xsd:documentation>
            Defines a Consumer Endpoint for the
            'org.springframework.integration.router.AbstractMessageProcessingRouter' implementation
            that serves as an adapter for invoking a method on any
            Spring-managed object as specified by the "ref" and "method" attributes.
        </xsd:documentation>
    </xsd:annotation>
</xsd:element>
So, it becomes pretty clear that we need some AbstractMessageProcessingRouter implementation to be present in the Java Configuration.
Also we have a paragraph in the Reference Manual like this:
  
With XML configuration and Spring Integration Namespace support, the XML Parsers hide how target beans are declared and wired together. For Java & Annotation Configuration, it is important to understand the Framework API for target end-user applications.
According your expression="payload.name" we need to look for the ExpressionEvaluatingRouter and then also read a chapter about @Bean configuration:
    @Bean
    @Router(inputChannel = "channel_in")
    public ExpressionEvaluatingRouter expressionRouter() {
        ExpressionEvaluatingRouter router = new ExpressionEvaluatingRouter("payload.name");
        router.setDefaultOutputChannelName("channel_default");
        router.setChannelMapping("foo", "channel_one");
        router.setChannelMapping("bar", "channel_two");
        return router;
                thank you, how do i handle this router based on an attribute value of an object, i have a Account object in which based on the type of object i should be able to route it to respective channels, also how do i define DirectChannel using java
– user10270958
                Aug 27, 2018 at 17:35
                Well, you still continue to use the SpEL against that Account payload. The DirectChannel has to be declared as a @Bean. Please, bear in mind that Spring Integration is just a Spring Framework extension for EIP, but it is still Spring, therefore everything is a bean and you should follow existing Java & Annotation rules to declare Spring Integration components.
– Artem Bilan
                Aug 27, 2018 at 17:45
                Good, but do you really have a @EnableIntegration on some @Configuration class? docs.spring.io/spring-integration/docs/current/reference/html/…
– Artem Bilan
                Aug 27, 2018 at 17:54
                Good. So, you route a check message to the checkChannel, but is there anything who consumes this channel, e.g. @ServiceActivator? Maybe it's time for you to come back to documentation to understand how Spring Integration works?
– Artem Bilan
                Aug 27, 2018 at 18:34
                yes i have that but there was a spell issue on the Service Activator channel definition, any ways thanks for guiding me
– user10270958
                Aug 27, 2018 at 18:37
        
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